Chapter 8 · Parametric Equations

Parametric Equations — Complete Guide

Parametric form, eliminating the parameter, orientation, common curve types, projectile motion, and real-world applications — with three elimination methods worked step-by-step.

What Are Parametric Equations?

Instead of writing y as a function of x, parametric equations express both x and y as functions of a third variable — the parameter, usually called t.

Rectangular form
y = f(x)
No direction information
Parametric form
x = f(t)
y = g(t)
Includes direction (orientation)

Why Use Parametric Form?

Direction: Parametric equations show which way the curve is traversed as t increases — rectangular form cannot.
Loops and revisited points: Curves that cross themselves (cycloids, Lissajous figures) cannot be written as y = f(x) at all.
Physics: Projectile motion naturally decomposes into separate x(t) and y(t) functions of time.

Common Parametric Forms

CurveParametric Form
Line segmentx = x₁ + (x₂−x₁)t, y = y₁ + (y₂−y₁)t, 0 ≤ t ≤ 1
Circlex = h + r cos t, y = k + r sin t, 0 ≤ t ≤ 2π
Ellipsex = h + a cos t, y = k + b sin t
Parabola (horizontal)x = at², y = 2at
Projectile motionx = v₀ cos θ · t, y = v₀ sin θ · t − ½gt²

Three Methods for Eliminating the Parameter

1

Method 1: Solve for t and substitute

x = 2t − 1, y = t² + 3

  1. 1.Solve the simpler equation for t: x = 2t − 1 → t = (x + 1)/2
  2. 2.Substitute into y = t² + 3:
  3. 3.y = ((x + 1)/2)² + 3
  4. 4.y = (x + 1)²/4 + 3
  5. 5.Answer: y = (x + 1)²/4 + 3 (a parabola, opening upward)

Restriction: t ∈ ℝ means x ∈ ℝ, so no domain restriction needed

2

Method 2: Pythagorean identity

x = 4 cos t, y = 3 sin t, 0 ≤ t ≤ 2π

  1. 1.Isolate the trig functions: cos t = x/4, sin t = y/3
  2. 2.Apply identity cos²t + sin²t = 1:
  3. 3.(x/4)² + (y/3)² = 1
  4. 4.Answer: x²/16 + y²/9 = 1 (an ellipse with a = 4, b = 3)

Full cycle: t from 0 to 2π traces the complete ellipse counterclockwise

3

Method 3: Trig identity (tan/sec)

x = sec t, y = tan t, −π/2 < t < π/2

  1. 1.Recall the identity: sec²t − tan²t = 1
  2. 2.Since x = sec t and y = tan t: x² − y² = 1
  3. 3.Answer: x² − y² = 1 (right branch of a hyperbola, since sec t ≥ 1 means x ≥ 1)

The domain restriction t ∈ (−π/2, π/2) limits the curve to the right branch

Orientation — Direction of Travel

Orientation is the direction the curve is traced as t increases. On graphs, orientation is shown with arrows pointing in the direction of increasing t.

Finding orientation

Plug in a few increasing values of t and plot. The sequence of points gives the direction.

x = cos t, y = sin t
t = 0: (1, 0)
t = π/2: (0, 1)
t = π: (−1, 0)
→ counterclockwise circle

Reversing orientation

Replace t with −t (or negating the parameter) reverses direction.

x = cos(−t), y = sin(−t)
= cos t, −sin t
→ clockwise circle
Same rectangular form (x²+y²=1)

Key point: Two parametric sets can produce the same rectangular equation but different orientations. On exams, you must identify orientation from the parametric form — not from the rectangular form.

Projectile Motion — The Classic Application

Standard Projectile Equations

x(t) = v₀ cos θ · t + x₀
y(t) = − ½g t² + v₀ sin θ · t + y₀
v₀ = initial speed, θ = launch angle
g = 32 ft/s² (feet) or 9.8 m/s² (meters)
x₀, y₀ = initial position (often 0)
t = time in seconds

Worked Example

A ball is kicked at 60 ft/s at 30° above horizontal from ground level. Find: (a) max height, (b) time of flight, (c) range.

Setup: x = 60 cos(30°) · t = 30√3 · t, y = −16t² + 60 sin(30°) · t = −16t² + 30t

(a) Max height: dy/dt = −32t + 30 = 0 → t = 30/32 = 15/16 sec

y(15/16) = −16(15/16)² + 30(15/16) = −225/16 + 450/16 = 225/16 ≈ 14.1 ft

(b) Time of flight: y = 0 → −16t² + 30t = 0 → t(−16t + 30) = 0 → t = 0 or 15/8 sec

(c) Range: x(15/8) = 30√3 · (15/8) = 450√3/8 ≈ 97.4 ft

Frequently Asked Questions

What is the difference between parametric and rectangular equations?

A rectangular equation directly relates x and y, like y = x² + 1. A parametric equation expresses both x and y as separate functions of a third variable called the parameter (usually t): x = f(t), y = g(t). The parameter adds information that rectangular form loses — specifically, the direction of travel along the curve and time-dependent behavior. For example, x = cos t, y = sin t traces a unit circle counterclockwise, while x = cos(-t), y = sin(-t) traces the same circle clockwise. Rectangular form (x² + y² = 1) cannot show this distinction.

How do you eliminate the parameter from parametric equations?

There are three main methods: (1) Solve one equation for t, then substitute into the other — works well for linear x(t) or y(t). (2) Use a Pythagorean identity — works when x = a·cos t and y = b·sin t (use cos²t + sin²t = 1). (3) Use other trig identities — when equations involve tan, sec, etc. Example: x = 3cos t, y = 2sin t → x/3 = cos t, y/2 = sin t → (x/3)² + (y/2)² = 1, which is an ellipse.

What is orientation in a parametric curve?

Orientation is the direction in which the curve is traced as the parameter t increases. When you graph a parametric curve, you draw arrows showing this direction of travel. For example, x = t, y = t² has orientation moving left-to-right (x increases as t increases). Orientation is lost when you convert to rectangular form — y = x² looks the same whether you move left or right. On exams, orientation is shown with arrows on the curve.

Practice parametric equations

Elimination, orientation, projectile motion — all with step-by-step solutions. Free to start, no account needed.

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